# How do you find a possible value for a if the points (-2,a), (6,1)has a distance of #d=4sqrt5#?

##### 2 Answers

#### Answer:

#### Explanation:

#"using the "color(blue)"distance formula"#

#•color(white)(x)d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

#"let "(x_1,y_1)=(6,1)" and "(x_2,y_2)=(-2,a)#

#d=sqrt((-2-6)^2+(a-1)^2)=4sqrt5#

#rArrsqrt(64+(a-1)^2)=4sqrt5#

#color(blue)"square both sides"#

#rArr64+(a-1)^2=80#

#"subtract 64 from both sides"#

#(a-1)^2=16#

#color(blue)"take the square root of both sides"#

#rArra-1=+-sqrt16larrcolor(blue)"note plus or minus"#

#rArra=1+-4#

#rArra=1-4=-3" or "a=1+4=5#

#### Answer:

**Possible values of** **are**

#### Explanation:

Distance between two points

Distance between two points

sides we get ,

Possible values of