How do you find a standard form equation for the line with (-2,-4) with a slope of 3?

1 Answer
Aug 30, 2016

#y=3x+2#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))#
where m represents the slope and #(x_1,y_1)# a point on the line.

here m = 3 and #(x_1,y_1)=(-2,-4)#

substitute these values into the equation.

#rArry+4=3(x+2)" is equation in point-slope form"#

It is usual, however, to distribute the bracket and collect like terms.

#y+4=3x+6rArry=3x+2" in slope-intercept form"#