# How do you find a standard form equation for the line with (-2,-4) with a slope of 3?

Aug 30, 2016

$y = 3 x + 2$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{point-slope form}}$ is

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{y - {y}_{1} = m \left(x - {x}_{1}\right)} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where m represents the slope and $\left({x}_{1} , {y}_{1}\right)$ a point on the line.

here m = 3 and $\left({x}_{1} , {y}_{1}\right) = \left(- 2 , - 4\right)$

substitute these values into the equation.

$\Rightarrow y + 4 = 3 \left(x + 2\right) \text{ is equation in point-slope form}$

It is usual, however, to distribute the bracket and collect like terms.

$y + 4 = 3 x + 6 \Rightarrow y = 3 x + 2 \text{ in slope-intercept form}$