How do you find a standard form equation for the line with (4,-3) and is parallel to the line 2x+3y-6=0?

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Answer 1 · 2016-07-28T23:11:58

#y = -2/3x -1/3#

Lines which are parallel have the same slope.
Find the equation of the given line by changing it into standard form. #y = mx +c#

#2x + 3y -6 =0" "rArr3y = -2x +6#

#y = -2/3x +2" "m= -2/3#

We also have a point on the line, #(4,-3)#

Use the formula: #y-y_1 = m(x-x_1)#

#y -(-3) =-2/3(x-4)#

#y+3 = -2/3x +8/3#

#y = -2/3x +8/3 -3" "2 2/3 -3#

#y = -2/3x -1/3#