How do you find a standard form equation for the line with A(2, −4) and is parallel to the line 5x-2y=4?

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Answer 1 · 2016-06-16T10:35:55

The desired line is #5x-2y-18=0#

A line parallel to #Ax+By+C=0# will always be of the form

#Ax+By+k=0#.

Hence a line parallel to #5x-2y=4# would be #5x-2y+k=0#

Putting the values of point #(2,-4)# in this, we get

#5xx2-2xx(-4)+k=0# i.e.

#10+8+k=0# or #k=-18#

Hence equation is #5x-2y-18=0#