How do you find abs( 2-3i )? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Shwetank Mauria Mar 25, 2016 |2-3i|=3.606 Explanation: Finding |2-3i| means finding the modulus of complex number 2-3i. As modulus of a complex number a+bi is given by sqrt(a^2+b^2) |2-3i|=sqrt(2^2+(-3)^2)=sqrt(4+9)=sqrt13=3.606 Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number 3+4i in the complex plane? How do I graph the complex number 2-3i in the complex plane? How do I graph the complex number -4+2i in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number 4i in the complex number plane? How do I use graphing in the complex plane to add 2+4i and 5+3i? How do I use graphing in the complex plane to subtract 3+4i from -2+2i? See all questions in Complex Number Plane Impact of this question 3948 views around the world You can reuse this answer Creative Commons License