How do you find $| - 3 + 4 i |$ $abs( -3+4i)$ ?

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Answer 1 · 2016-03-30T13:30:51

$| - 3 + 4 i | = \sqrt{{(- 3)}^{2} + 4^{2}} = 5$ $|-3+4i|=sqrt((-3)^2+4^2)=5$

Let $z = x + i y$ $z=x+iy$ be any complex number in rectangular form.

Then its modulus is given by $| z | = \sqrt{x^{2} + y^{2}}$ $|z|=sqrt(x^2+y^2)$ .

So in this case we get

$| - 3 + 4 i | = \sqrt{{(- 3)}^{2} + 4^{2}} = \sqrt{25} = 5$ $|-3+4i|=sqrt((-3)^2+4^2)=sqrt25=5$

How do you find |−3+4i|abs( -3+4i)?