Question

How do you find `abs(-4 + 3i)`?

Answer 1

`|-4+3i|=5`

Explanation:

Absolute value of a complex number `a+ib` is denoted as `|a+ib|`

and is given by `sqrt(a^2+b^2)`

Hence absolute value `|-4+3i|` is

`sqrt(4^2+3^2)=sqrt(16+9)=sqrt25=5`