How do you find $abs(-4 + 3i)$ ?

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Answer 1 · 2016-05-23T14:03:06

$|-4+3i|=5$

Absolute value of a complex number $a+ib$ is denoted as $|a+ib|$

and is given by $sqrt(a^2+b^2)$

Hence absolute value $|-4+3i|$ is

$sqrt(4^2+3^2)=sqrt(16+9)=sqrt25=5$

How do you find abs(-4 + 3i)abs(-4 + 3i)?