How do you find all sets of three consecutive even integers whose sum is between 25 and 45?
1 Answer
Mar 12, 2016
solutions are: 8 10 12
or 10,12,14
or 12,14,16
Explanation:
Let the first even number be n. The sum will be n+n+2+n+4=3 n + 6 and
25 < 3 n + 6 < 45.
19<3n<39
So,
possible values of n = 8,10,12
For the starter n = 8, the sum is 8 + 10 +12 = 30.
for n= 10 there exists thee numbers 10.12,14,where sum =36
for n= 12 there exists thee numbers 12,14,16,where sum =42
Hence sets of three consecutive numbers are
set1
or
set2
or
set3