# How do you find all six trigonometric function of theta if the point (-3,-4) is on the terminal side of theta?

$\tan t = \frac{y}{x} = \frac{- 4}{-} 3 = \frac{4}{3}$
$\cot t = \frac{1}{\tan} = \frac{3}{4}$
${\cos}^{2} t = \frac{1}{1 + {\tan}^{2} t} = \frac{1}{1 + \frac{16}{9}} = \frac{9}{25}$
$\cos t = - \frac{3}{5}$ (cos t negative because t is in Q. 3)
$\sin t = \cos t . \tan t = \left(- \frac{3}{5}\right) \left(\frac{4}{3}\right) = - \frac{4}{5}$
$\sec t = \frac{1}{\cos} = - \frac{4}{3}$
$\csc t = \frac{1}{\sin} = - \frac{5}{4}$