How do you find all the real and complex roots of x^2 - 2x +1 = 0?

Jan 18, 2016

$x = 1$

Explanation:

This polynomial is a perfect square. It factors into

${\left(x - 1\right)}^{2} = 0$

Solve the equation by taking the square root of both sides.

$x - 1 = 0$

$x = 1$

This is the equation's only root. It has a multiplicity of $2$.