How do you find all the real and complex roots of #x^2 - 2x +1 = 0#?
1 Answer
Jan 18, 2016
Explanation:
This polynomial is a perfect square. It factors into
#(x-1)^2=0#
Solve the equation by taking the square root of both sides.
#x-1=0#
#x=1#
This is the equation's only root. It has a multiplicity of
