How do you find all the real and complex roots of #x^2 - 2x +1 = 0#?

1 Answer
Jan 18, 2016

Answer:

#x=1#

Explanation:

This polynomial is a perfect square. It factors into

#(x-1)^2=0#

Solve the equation by taking the square root of both sides.

#x-1=0#

#x=1#

This is the equation's only root. It has a multiplicity of #2#.