# How do you find all the real and complex roots of #(x^ 2 + 4)(x + 5)^2 = 0#?

##### 1 Answer

Feb 7, 2016

#### Explanation:

(x^2+4)(x+5)^2=0

if a*b=0, then a=0 or b=0:

so:

The first part has not real solutions, since

but has complex roots:

The second part is easy to resolve: