Question

How do you find all the zeros of `F(x) = 8(x-6)(x+6)^5` with all its multiplicities?

Answer 1

We have two zeros `6` with multilicity of `1` and `-6` with multiplicity of `5`.

Explanation:

Zeros of `f(x)=k(x-alpha)^a(x-beta)^b(x-gamma)^c`

are `alpha` with multiplicity of `a`, `beta` with multiplicity of `b` and `gamma` with multipicity of `c`.

Hence in `f(x)=8(x-6)(x+6)^5`

we have two zeros `6` with multilicity of `1` and `-6` with multiplicity of `5`.