How do you find all the zeros of #F(x) = 8(x-6)(x+6)^5# with all its multiplicities?

1 Answer
Jan 23, 2018

Answer:

We have two zeros #6# with multilicity of #1# and #-6# with multiplicity of #5#.

Explanation:

Zeros of #f(x)=k(x-alpha)^a(x-beta)^b(x-gamma)^c#

are #alpha# with multiplicity of #a#, #beta# with multiplicity of #b# and #gamma# with multipicity of #c#.

Hence in #f(x)=8(x-6)(x+6)^5#

we have two zeros #6# with multilicity of #1# and #-6# with multiplicity of #5#.