Question

How do you find all zeros of `f(x)=1/3x^2+1/3x-2/3`?

Answer 1

Zeros of `f(x)` are `x=1` and `x=-2`.

Explanation:

`f(x)=1/3x^2+1/3x-2/3=1/3(x^2+x-2)`

= `1/3(x^2+2x-x-2)`

= `1/3(x(x+2)-1(x+2))`

= `1/3(x-1)(x+2)`

Hence, zeros of `f(x)` are `x=1` and `x=-2`.