How do you find all zeros of #h(t)=t^2-6t+9#?

1 Answer
Mar 5, 2018

Answer:

3, that is the only root of #h(t)#.

Explanation:

#h(t)# is a quadratic in #t# which is :
#h(t)=t^2-6t+9#
to find its zeros we equate the function with 0.
#h(t) = 0 => t^2-6t+9 = 0#

Now by splitting the middle term,
#=>t^2 -3t -3t +9= 0#
#=>t(t-3)-3(t-3) = 0#
#=>(t-3)(t-3) = 0#

Hence the root is 3.