Question

How do you find all zeros of the function `f(x) = 4(x + 7)^2(x - 7)^3`?

Answer 1

Zeros of `f(x)=4(x+7)^2(x-7)^2` are `-7` and `7`.

Explanation:

If `f(x)=u(x-a)^m(x-b)^n(x-c)^p(x-d)^q`, a multiplication of number of binomials of degree one, then zeros of polynomials are `a`, `b`, `c` and `d`, as any of them when put in place of `x` will make `f(x)=0`. Here `u` is just a constant.

Hence, zeros of `f(x)=4(x+7)^2(x-7)^2` are `-7` and `7`.