How do you find an equation of the parabola with vertex (3,2) and focus (1,2)?
1 Answer
Jan 12, 2017
Explanation:
Focus S and Vertex V:
(1, 2)S-------V(1, 2)
The level SV is y = the common value of
V is ahead of S. So, the axis is in the negative
x-direction.
The perpendicular tangent at the vertex VT is given by
Now, the equation of this parabola, with size a = 2, axis
and tangent at the vertex x = 2 is
graph{((y-2)^2+8(x-3))(x-3)(y-2)=0 [-20, 20, -10, 10]}