# How do you find an equation of the parabola with vertex (3,2) and focus (1,2)?

##### 1 Answer

Jan 12, 2017

#### Explanation:

Focus S and Vertex V:

(1, 2)S-------V(1, 2)

The level SV is y = the common value of

V is ahead of S. So, the axis is in the negative

x-direction.

The perpendicular tangent at the vertex VT is given by

Now, the equation of this parabola, with size a = 2, axis

and tangent at the vertex x = 2 is

graph{((y-2)^2+8(x-3))(x-3)(y-2)=0 [-20, 20, -10, 10]}