How do you find #(d^2y)/(dx^2)# for #5=2x-5y^2#?
1 Answer
Dec 22, 2016
Explanation:
It would be possible to explicit
Differentiate the equation:
term by term with respect to
So, we have:
Solving for
Differentiating again:
Now from the original equation we have:
and we can use this to substitute