Question

How do you find `(dy)/(dx)` given `2x^2+y^2=4`?

Answer 1

`d/dx(2x^2 + y^2) = d/dx(4)`

`4x + 2y(dy/dx) = 0`

`2y(dy/dx) = -4x`

`dy/dx = (-4x)/(2y)`

`dy/dx = (-2x)/y`

Hopefully this helps!