How do you find exact value of #sin (pi/ 6)#?

2 Answers
Apr 27, 2018

#1/2#

Explanation:

For trigonometry, it is imperative to memorize a tool known as the Unit Circle. This is a circle with a radius of #1# and a center on the origin. The points on the circumference of the circle are the coordinates that you need to know.

When you see a trigonometric function such as sine (or sin(#theta#)) or cosine (or cos(#theta#)), it refers the point on the circumference of the circle that intersects the line coming from the origin at a given angle (#theta#) counter-clockwise from the axis between Quadrant I and Quadrant IV of the coordinate plane.

In this case, #pi/6# refers to the angle in radians, an alternate unit of measurement for angles (#pi# rad = 180°). The point on the unit circle that is intersected by this line is (#sqrt(3)/2#, #1/2#). Finally, the function, sin(#theta#) returns a value equal to the y-coordinate of the point, giving us an answer of #1/2#.

In the future, you should memorize all the major points on the unit circle along with their reference angles and you'll be able to find these answers quickly.

Apr 28, 2018

#sin (pi/6) = 1/2#

Explanation:

The fastest way is to look at the trig table, titled "Trig Functions of Special Arcs".
This table gives --> #sin (pi/6) = 1/2#.
Second method.
Use trig identity: sin (a - b) = sin a.cos b - sin b.cos a
#sin (pi/6) = sin (pi/2 - pi/3) #=
#= sin (pi/2).cos (pi/3) - sin (pi/3).cos (pi/2)#
Reminder. #cos (pi/2) = 0#, #sin (pi/2) = 1#, and #cos (pi/3) = 1/2#
Finally,
#sin (pi/6) = (1)(1/2) - 0 = 1/2#