# How do you find (f of g of h) given f(x)=x^2+1 g(x)=2x and h(x)=x-1?

Dec 28, 2015

See solution below

#### Explanation:

ƒ(g(h(x)))

= ƒ(g(x - 1)
= ƒ(2(x - 1))
= ƒ(2x - 2)
= ƒ(2x - 2)^2 + 1
= $4 {x}^{2}$ - 8x + 4 + 1
= $4 {x}^{2}$ - 8x + 5

So, ƒ(g(h(x))) = $4 {x}^{2}$ - 8x + 5

I hope I properly understood your question!