# How do you find its vertex, axis of symmetry, y-intercept and x-intercept for #f(x) = x^2 - 4x#?

##### 1 Answer

Apr 21, 2018

#### Answer:

Vertex is

#### Explanation:

This is the equation of parabola. **Intercept form** of equation of parabola is

As we have

**Vertex form** of equation of parabola is

Here we have

Hence axis of symmetry is

graph{(x^2-4x-y)(x-2)((x-2)^2+(y+4)^2-0.03)=0 [-9.92, 10.08, -5.12, 4.88]}