# How do you find lim root3(x+2) as x->oo?

Substitute $y = x + 2$.
${\lim}_{x \to \infty} y = {\lim}_{x \to \infty} x + 2 = \infty$
${\lim}_{x \to \infty} \sqrt[3]{x + 2} = {\lim}_{y \to \infty} \sqrt[3]{y} = + \infty$