How do you find #\log _ { 2} [ 32( x ^ { 2} - 4) ]#?
1 Answer
Dec 13, 2016
For problems like these, we expand the logarithms using the sum and difference rules and evaluate if possible.
#=log_2(32) + log_2(x^2 - 4)#
#= log32/log2 + log_2(x + 2)(x - 2)#
#= (log2^5)/log2 + log_2(x + 2) + log_2(x - 2)#
#= (5log2)/log2 + log_2 (x + 2) + log_2 (x - 2)#
#=5 + log_2 (x +2) + log_2 (x- 2)#
Hopefully this helps!
