How do you find the 6 trigonometric functions for 3pi/2?

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How do you find the 6 trigonometric functions for 3pi/2?

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Answer 1 · 2015-10-01T10:09:08

$3pi/2$ = 2 $pi$ - $pi/2$ . Sin [ 2 $pi$ - $pi/2$ ] = - sin $pi/2$ = -1
cos[2 $pi$ - $pi/2$ ] = cos $pi/2$ = 0.
tan[2 $pi$ - $pi/2$ ] = - tan $pi/2$ = -1/0 (undefined).

Explanation:

csc $3pi/2$ = - 1, sec $3pi/2$ = 1/0 (undefined) and cot $3pi/2$ = 0.

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How do you find the 6 trigonometric functions for 3pi/2?

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