# How do you find the amplitude and period of a function y=-3tan(pi(x))?

The tangent function has no amplitude. The period of this function, calculated using $p = \frac{\pi}{b}$ (a formula used for finding the period of any tangent or cotangent function) where $b = \pi ,$ is $1.$
The period of the tangent and cotangent functions, when in the form $y = \tan \left(b x\right)$ and $y = \cot \left(b x\right)$ are given by $p = \frac{\pi}{b}$.
Here, we see $b = \pi$, so $p = \frac{\cancel{\pi}}{\cancel{\pi}} = 1$.