How do you find the amplitude and period of a function #y= -4 cos 2x#?

1 Answer
Feb 10, 2017

#"amplitude "=4," period"=pi#

Explanation:

The standard form of the #color(blue)"cosine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b" and vertical shift "=d#

#"here "a=-4,b=2,c=0,d=0#

#rArr"amplitude "=|-4|=4" and period "=(2pi)/2=pi#