Question

How do you find the amplitude and period of a function `y = sin(pi/2Ө)`?

Answer 1

Amplitude`=1`

Period `=4`

Explanation:

from the given `y=sin (pi/2* theta)`

it should be taken into account that the above is the same as

`y=1*sin (pi/2* theta)`

Take the absolute value of any number you see as numerical coefficient of sine or cosine expression and you get the Amplitude.

Amplitude `=abs1=1`

The Period can be obtain using `P=(2pi)/a` where `a` is the number beside `theta`

so that `P=(2 pi)/abs(pi/2)=4`

Learn from the following examples,

`y=-7*sin 3theta`
Amplitude`=abs-7=7` and Period`=(2pi)/abs(3)=(2pi)/3`

`y=-3/4*cos ((pitheta)/6)`

Amplitude`=abs(-3/4)=3/4`and Period`=(2pi)/abs(pi/6)=12`

`y=12*sin (theta)`

Amplitude`=abs(12)=12`and Period`=(2pi)/abs(1)=2pi`

I hope the additional examples help..

Have a nice day from the Philippines ....