# How do you find the amplitude and period of a function y = -tan(x - pi/2)?

Jan 10, 2016

An explanation is given below.

#### Explanation:

The $A \tan \left(B \left(x - C\right)\right) + D$ function has $\textcolor{red}{\text{no amplitude.}}$
The period is given by $\frac{\pi}{B}$

$y = - \tan \left(x - \frac{\pi}{2}\right)$
On comparing with $A \tan \left(B \left(x - C\right)\right) + D$
We can see $B = 1$

The period is $\frac{\pi}{1} = \pi$

The period of the given function is $\pi$