Question

How do you find the amplitude and period of `y=2csc2x`?

Answer 1

Period of y = 2csc 2x
Ans: `pi`

Explanation:

`y = csc 2x = 1/(2sin 2x)`
The period of sin x is `2pi`. The period of sin 2x is `pi`.
The period of csc 2x is also `pi`.