Question

How do you find the amplitude and period of `y=2sec(4/5theta)`?

Answer 1

Amplitude is `2`.
Period is `(5pi)/2` or `7.85398163`.

Explanation:

Standard Form: `y=asecb(x-c)+d`
Equation: `y=2sec(4/5theta)`
`a=2`
`b=4/5`
`c=`none
`d=`none

AMPLITUDE
amplitude = distance from middle of graph (y=0) to highest and lowest points on graph
formula: `|a|`
`|2|`
`2`
Amplitude is `2`.

PERIOD
period = interval in which the graph repeats itself
formula: `(2pi)/|b|`
`(2pi)/|4/5|`
`(2pi)/(4/5)`
`2pi-:4/5`
`2pi*5/4`
`(10pi)/4`
`(5pi)/2 = 7.85398163`
Period is `(5pi)/2` or `7.85398163`.