How do you find the amplitude and period of y=2sin.5x?

Sep 12, 2015

Amplitude is $2$ and period is $4 \pi$

Explanation:

The amplitude $A$ is represented by the number in front of the $\sin$ function so:
$A = 2$
The period is given as $\frac{2 \pi}{k}$ where $k$ is the number in front of $x$ in the argument of $\sin$:
so period$= \frac{2 \pi}{0.5} = 4 \pi \approx 12.5$ that represents the interval needed to complete one oscillation.
Graphically:
graph{2*sin(0.5x) [-16.02, 16.02, -8.01, 8.01]}