Question

How do you find the amplitude and period of `y=3/4cos(1/2theta)`?

Answer 1

Amplitude = 3/4 & Period = `4pi`

Explanation:

Standard form `y=a*cos(b(theta)+c)+d`
Where a is Amplitude and `(2pi)/b` is period
`a=(3/4)` & period `=(2pi)/(1/2)=4pi`