# How do you find the amplitude and period of y=5csc3theta?

Jun 1, 2018

$A m p l i t u \mathrm{de} = | A | = 5$

Period $= \frac{2 \pi}{|} B | = \frac{2 \pi}{3}$

#### Explanation:

$y = A \csc \left(B x - C\right) + D$

$y = 5 \csc 3 \theta$

$A = 5 , B = 3$

$A m p l i t u \mathrm{de} = | A | = 5$

Period $= \frac{2 \pi}{|} B | = \frac{2 \pi}{3}$

Phase Shift $= - \frac{C}{B} = 0$

Vertical Shift $= D = 0$