# How do you find the amplitude and period of #y= -5sinx#?

##### 1 Answer

Sep 22, 2015

Amplitude :

Period :

#### Explanation:

A little explanation would be quite adequate for this problem.

- To determine the Amplitude, put the
*smallest*and*largest*values of#sinx# into the**function**.

You know,#-1\leq sinx\leq +1#

So,

The smallest value of the function,

The largest value of the function

So, the **Range**=

As amplitude is equal to the **largest value** of the Range,

**Amplitude** =

**Notice that [] braces. It carries some important information!**

- Now, look at the
#sinx# . Identity the**Coefficient of the angle, x**.

Assume,

The fundamental period#=P_f#

Fundamental period length#=P_l#

Coefficient of angle, x#=c#

Now,

Two**shorty, golden**equation for you,

Fundamental Period,#P_f=\frac{P_l}{2\pi}#

Period,#P=\frac{P_f}{c}#

Combining Them you get,

#P_f=\frac{P_l}{2\pic}#

For your given function,#y= -5sinx#

#P_l=2\pi#

#c=1#

So, **Period of the function**

A piece of cake isn't it?

Now can you say the **Amplitude** and **Period** of this function?

Happy Problem Solving!!!