How do you find the amplitude and period of #y=6sin(1/8x)#?

1 Answer
Aug 27, 2016

amplitude = 6, period #=16pi#

Explanation:

The standard form of the #color(blue)"sine function"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))#

where amplitude = |a| , period#=(2pi)/b#

phase shift #=-c/b" and vertical shift" =d#

here a = 6 , #b=1/8# , c = 0 and d = 0

#rArr"amplitude" =|6|=6" and period"=(2pi)/(1/8)=16pi#