Question

How do you find the amplitude, period and graph `3/4y=2/3sin(3/5theta)`?

Answer 1

Amplitude `A = 8/9`
Period `=(2pi)/B=(2pi)/(3/5)=(10pi)/3`
Phase shift `=(-C/B)=0`

Explanation:

`y=(8/9)sin((3/5)theta)`
Amplitude `A = 8/9`
Period `=(2pi)/B=(2pi)/(3/5)=(10pi)/3`
Phase shift `=(-C/B)=0`
Vertical shift `D=0`

`y=(8/9)sin((3/5)theta)`
graph{(8/9)sin((3/5)x) [-10, 10, -5, 5]}