How do you find the amplitude, period and phase shift for #y=1/2cos(theta+90^circ)#?
1 Answer
Mar 1, 2017
Explanation:
The standard form of the
#color(blue)"cosine function"# is.
#color(red)(bar(ul(|color(white)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#
#"where amplitude "=|a|," period "=(360^@)/b#
#"phase shift "=-c/b" and vertical shift "=d#
#"here "a=1/2,b=1 ,c=90^@,d=0#
#rArr"amplitude "=|1/2|=1/2," period "=(360^@)/1=360^@#
#"phase shift "=-90^@/1=-90^@#
