# How do you find the amplitude, period and phase shift for y=4sin(theta-60^circ)-1?

Jun 1, 2018

As below

#### Explanation:

Standard Form $y = A \sin \left(B x - C\right) + D$

Given : $y = 4 \sin \left(\theta - {60}^{\circ}\right) - 1$

$y = 4 \sin \left(\theta - \left(\frac{\pi}{3}\right)\right) - 1$

$A m p l i t u \mathrm{de} = A = | A | = 4$

Period $= \frac{2 \pi}{|} B | = 2 \pi$

Phase Shift $= - \frac{C}{B} = \frac{\pi}{3}$, $\frac{\pi}{3}$ to the right.

Vertical Shift $D = - 1$