How do you find the amplitude, period and phase shift for #y=4sin(theta-60^circ)-1#?

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Answer 1 · 2018-06-01T03:15:37

As below

Standard Form #y = A sin (Bx -C) + D#

Given : #y = 4 sin (theta - 60^@) -1#

#y = 4 sin (theta - (pi/3)) - 1#

#Amplitude = A = |A| = 4#

Period # = (2pi)/|B| = 2pi#

Phase Shift # = -C / B = pi / 3#, #pi/3# to the right.

Vertical Shift # D = -1#