How do you find the amplitude, period and phase shift for #y=sin(theta+pi)#?

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Answer 1 · 2018-03-01T09:44:08

Amplitude # = 1#

Period # = 2pi#

Phase shift # = -pi# #pi# to the left

Use the form #y = a sin (bx - c) + d# to find amplitude, period and phase shift.

Given #y = sin (theta + pi)#

Amplitude # = a = 1#

Period # = pi / | b | = (2pi) / 1 = 2pi#

Phase shift # = c / b = -pi# #pi# to the left

graph{sin (x + pi) [-10, 10, -5, 5]}