# How do you find the amplitude, period and phase shift for y=sin(theta+pi)?

##### 1 Answer
Mar 1, 2018

Amplitude $= 1$

Period $= 2 \pi$

Phase shift $= - \pi$ $\pi$ to the left

#### Explanation:

Use the form $y = a \sin \left(b x - c\right) + d$ to find amplitude, period and phase shift.

Given $y = \sin \left(\theta + \pi\right)$

Amplitude $= a = 1$

Period $= \frac{\pi}{|} b | = \frac{2 \pi}{1} = 2 \pi$

Phase shift $= \frac{c}{b} = - \pi$ $\pi$ to the left

graph{sin (x + pi) [-10, 10, -5, 5]}