Question

How do you find the amplitude, period and phase shift of `y= -sin (4/3)x`?

Answer 1

Amplitude `=1`
Period `=(3pi)/2`
Phase shift`=0`

Explanation:

From the given equation
`y=-sin(4/3)x`

Amplitude `=abs(-1)=1`

Period `=(2pi)/(4/3)=(2pi)/1*(3/4)=(3pi)/2`

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