Question

How do you find the amplitude, period, and phase shift of `y=sin 4x + 5`?

Answer 1

Amplitude = 1, Period = `pi / 2`,

Phase shift `= -(5/4)`, `color(white)(aaa) (5/4)` to the left

Explanation:

`y = sin(4x + 5)`

`Amplitude = a = 1`

`Period = (2pi)/|b| = (2pi) / 4 = pi/2`

Phase shift `= -c / b = -5 / 4`, `color(white)(aaa) (5/4)` to the left

graph{sin (4x + 5) [-10, 10, -5, 5]}