How do you find the amplitude, period, and shift for #y = 2sin (2x - pi) +1#?

1 Answer
Jun 1, 2016

#2 , pi,-pi#

Explanation:

The standard form of the #color(blue)"sine wave function"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))#

where amplitude = |a| , period# =(2pi)/b# , c is the phase shift and
d, the vertical shift.

here amplitude = |2| = 2 , period#=(2pi)/2=pi#

phase shift #=-pi" and vertical shift "=((0),(1))#