# How do you find the amplitude, period, and shift for y=3Sin(2x)?

Amplitude$= 3$;Period$= \pi$ ; Shift $= 0$
Compare with the general sinusoidal function$y = A \sin \left(B x + C\right) + D$
here A=3 ; B=2*x; C=0, D=0 Hence Amplitude $= | A | = 3$; Period $= 2 \cdot \frac{\pi}{|} B | = 2 \cdot \frac{\pi}{2} = \pi$; Phase Shift $= 0$ (since C=0); Vertical Shift $= 0$ (since D=0)