How do you find the amplitude, period, and shift for $y = cos (x - 60) + 2$ $y=cos (x-60)+2$ ?

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How do you find the amplitude, period, and shift for $y = cos (x - 60) + 2$ $y=cos (x-60)+2$ ?

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Answer 1 · 2017-05-08T18:59:20

$1, 360^{\circ}, + 60^{\circ}$ $1,360^@,+60^@$

Explanation:

$the standard form of the cosine function$ $"the standard form of the "color(blue)"cosine function"$ is.

$color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))$

$"where amplitude "=|a|," period "=360^@/b$

$"phase shift "=-c/b ," vertical shift "=d$

$"here " a=1,b=1,c=-60^@,d=2$

$rArr"amplitude "=|1|=1," period "=360^@$

$"phase shift "=-(-60^@)=+60^@$

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How do you find the amplitude, period, and shift for $y = cos (x - 60) + 2$ $y=cos (x-60)+2$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you find the amplitude, period, and shift for y=cos (x-60)+2y=cos(x−60)+2y=cos (x-60)+2?

1 Answer

Explanation:

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Impact of this question

How do you find the amplitude, period, and shift for $y = cos (x - 60) + 2$ $y=cos (x-60)+2$ ?