How do you find the amplitude, period, phase shift for #y=cos(x+pi/2)#?

1 Answer
Dec 23, 2016

#"amplitude " =1," period" =2pi," phase shift" =-pi/2#

Explanation:

The standard form of the #color(blue)"cosine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period " =(2pi)/b#

#"phase shift " =-c/b" and vertical shift " =d#

#"here " a=1,b=1,c=pi/2" and " d=0#

#rArr"amplitude" =|1|=1,"period " =(2pi)/1=2pi#

#"and phase shift " =-(pi/2)/1=-pi/2#