How do you find the amplitude, period, phase shift for #y=cos(x-pi/2)#?

1 Answer
Feb 27, 2017

Amplitude # = 1#

Period # = 2 pi#

Phase Shift # = - pi/2#

Explanation:

In a more generalised form, a cosine function can be written as:

#y = A cos (k x + psi)#, where:

  • #A# is the amplitude;

  • #k# is the wavenumber. Note that #k = (2 pi) / lambda#, where #lambda# is the wavelength or spatial period; and

  • Finally, #-psi/k# is the phase shift.

We can read these straight off the original equation as:

#A = 1#

#lambda = (2 pi) /k= (2 pi) /1 = 2 pi#

#-psi/k = - pi/2#

Note that this is the phase shift from a vanilla cosine function. Sines and cosines are the same but for a phase shift and so this could also be related to a sine function with a different shift.