# How do you find the amplitude, period, phase shift for y=sin1.5x?

Mar 1, 2018

Amplitude $a = 1$

Period $= \frac{2 \pi}{|} 1.5 | = 4.1888$

Phase shift $= \frac{c}{b} = \frac{0}{1.5} = 0$ (shift to the right)

#### Explanation:

Use the form $y = a \sin \left(b x - c\right) + d$

To find amplitude, period and phase shift.

Given $y = \sin \left(1.5 x\right)$

graph{sin(1.5x) [-10, 10, -5, 5]}

Amplitude $a = 1$

Period $= \frac{2 \pi}{|} 1.5 | = 4.1888$

Phase shift $= \frac{c}{b} = \frac{0}{1.5} = 0$ (shift to the right)