# How do you find the amplitude, period, phase shift for y=sin2(x+(3pi)/4)?

Jul 28, 2018

#### Explanation:

Compare this equation to

$y = a \sin \left(\omega x + \phi\right)$

Here,

$y = \sin 2 \left(x + \frac{3}{4} \pi\right) = \sin \left(2 x + \frac{3}{2} \pi\right)$

The amplitude is $a = 1$

The period is $T = 2 \frac{\pi}{2} = \pi$

The phase shift is $\phi = \frac{3}{2} \pi$

graph{sin(2x+3/2pi) [-7.02, 7.024, -3.51, 3.51]}