# How do you find the amplitude, period, phase shift for #y=sin2x#?

##### 1 Answer

Jan 31, 2017

#### Explanation:

The standard form of the

#color(blue)"sine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period " =(2pi)/b#

#"phase shift "=-c/b" and vertical shift "=d#

#"here "a=1,b=2,c=0,d=0#

#rArr"amplitude "=|1|=1," period "=(2pi)/2=pi# Since c = 0 there is no phase shift.