How do you find the amplitude, period, vertical and phase shift and graph #y=2/3cos(theta-50)#?

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Answer 1 · 2018-03-08T15:07:14

Amplitude = 2/3, Period = #2pi#

Phase shift = 50 to the right, Vertical shift = 0

Standard form of equation #y = a cos (bx - c) + d#

Where #Amplitude = a, Period = (2pi)/|b|, Phase# shift #= -c / b, vertical# shift #= d#

Given equation is #y = (2/3) cos (theta - 50)#

Amplitude #= a = (2/3)#

Period # = (2pi) / |b| = (2pi)#

Phase shift = -c / b = 50# to the right

Vertical shift # = d = 0#

graph{(2/3) cos (x - 50) [-10, 10, -5, 5]}